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muslim4life7

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muslim4life7 last won the day on October 11 2016

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About muslim4life7

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  1. Why Islam Is Only True Religion From God

    why a rational person should choose the Quran . This is only refering to a person who believes in 1 God and is searching for a religion. U have all the world scriptures Bible, Quran, Hindu books, Sikh books, Buddhist books, Avesta,(Zoroastrianism) etc Simple reason why accept Quran and reject the rest is because... THE QURAN GIVES YOU RATIONAL REASONS WHY TO ACCEPT IT NO OTHER BOOK DOES THAT !. The Quran REASONS WITH THE READER gives arguments 1.Why God exists (guidance for atheists reasoning with atheists) 2. Why he is 1 ( reasoning with Hindus, Buddhists, and other idol worshippers providing guidance) 3. Why he is not like his creation 4, Arguments for the afterlife e.g the resurrection rational arguments for the resurrection 5. Arguments why the Prophet pbuh is a true prophet 6.Arguments why the book itself is from God 7. Arguments showing Jesus is not son of God and not God (guidance for Christians) the list can go on and on point is Quran REASONS WITH THE READER PROVIDES RATIONAL ARGUMENTS WHY U SHOULD BELIEVE IN IT why u should accept Islam now my Question to the non muslims would be so u have ALL these scriptures all claim 2 be from God but only 1 out of them ALL give REASONS WHY 2 ACCEPT IT . So which book would u expect to be from God a book which gives u reasons to accept it or a book which doesnt give u any reason to accept it. Do u really think God will author a book and not give a single reason to accept it. The only way 2 disprove my point is 2 show other religious books reason with the reader and pprovide arguments why 2 accept it .As far as i know i cant find any. Bible is just a collection from many authors so are Hindu n Sikh scripture. Thats why most religions are not missionary religions dont command to preach .
  2. 14.14.FACT 5. Insert the sequence number of each letter in the word before its gematrical value in Fact 4. For example, the gematrical values of the letters in first word are 2 60 40. When we insert the sequence numbers of the letters, we get 1 2 2 60 3 40, where the sequence numbers are in italics, the gematrical values are in bold. Similarly, the gematrical values of the letters in the second word are 1 30 30 5. When we insert the sequence numbers of the letters, we get 1 1 2 30 3 30 4 5, and so on. When all the numbers are put together, the result is a 56-digit number that is a multiple of 19: 1 1 2 2 60 3 40 2 1 1 2 30 3 30 4 5 3 1 1 2 30 3 200 4 8 5 40 6 50 4 1 1 2 30 3 200 4 8 5 10 6 40 = 19 x 590843895848580686595 .
  3. Open challenge for anyone to imitate the miracle of number 19 in Bismillah The challenge is to combine 4 words and derive combinations of 19 in 1 FIXED METHOD Below the fixed method is 1,2,3,4 it could be JUST the number 1 because 1st chapter or 1,2,3,4 Letters in each word must be different from the bismillah 1. – If we write down the order number of each word followed by the number or letters in that word we get 13243646, which is a multiple of 19. (the order number for each word is written in red for distinction.): 366866 = 13243646 × 19. 2. – If after the order number for each word, the sum of Abjad values of its letters is placed, again a multiple of 19 will be obtained: 110226633294289 = 19 X 5801401752331 3. If after the order number of each word the Abjad value of each letter in that word is placed, again the resulting number will be divisible by 19: 1260402130305313020084050413020081040 = 19 × 66336954126595422109686863843162160 4. – If after the order number for each word, the sum of the number of letters of that world plus Abjad value sum of that word is placed, again the resulting number is a multiple of 19. Namely: 110527033354295 = 19 X 5817212281805; where (3 +102 = 105), (4 + 66 = 70), (6 + 329 = 335), (6 + 289 = 295) is used. 5. – If after the order number for each word, the sum of the number of letters of that word plus sum of the numbers of the letters of all previous words is placed, again the resulting number is divisible by 19: 1327313419 = 19 X 69858601., where; (0 + 3 = 3), (3 + 4 = 7), (3 + 4 + 6 = 13), (3 + 4 + 6 + 6 = 19) are used. 6. – If after the order number for each word, the sum of Abjad values of that word plus Abjad values of the all previous words is placed, again the ensuing number is a multiple of 19: 1102216834974786 = 19 X 58011412367094; where (102 + 66 = 168) (102 + 66 + 329 = 497), (102 + 66 + 329 + 289 = 786), is used. 7. FACT 6. Replace the total gematrical value of each word in Fact 3 by the sum of the gematrical values of the first and the last letter in that word. For instance, the total gematrical value of the first word, 102, is replaced by 42. The number 42 is the sum of 2 and 40, which are the gematrical values of the first and the last letter in the first word. Similarly, the total gematrical value of the second word, 66, is replaced by 6, the sum of 1 and 5. Repeating this process for the four words of the Basmalah, we get an 11-digit number that is a multiple of 19: 1 42 2 6 3 51 4 41 = 19 x 748755339 (2+40) (1+5) (1+50) (1+40) Pattern 8,9, 8. Lets write numerical value backwards so instead of 102 it will be 201 so 1 201 2 66 3 923 4 982 /19 =divisible 9. Now lets see numerical value of each letter going backwards so 2 60 40 will be written as 04062 1040622503031305048002031404018002031/19=divisible 3 4 is in ther aswell 10. 1 10 2 19 3 102 66 329 289 4 786 /19 =58010163298068047094 how did i get 10 1+2+3+4=10 11. – If the order number of each word (1, 2, 3, 4) is placed after the corresponding underlined digits groups above, a 66-digit number is ensued which is again a multiple of 19: 216024031 14305306572 1830920010811401250133 114301520016817101840194 =19 X 113696855849…). 12. . lets add total numerical value of each word with total numerical value of each letter with number of letters so e.g 102+2+60+40+3= 207 so 207 1 136 2 664 3 584 4 /19 = divisible no remainder 13. - Insert the sequence number of each letter in the word before its gematrical value in Fact 4. For example, the gematrical values of the letters in first word are 2 60 40. When we insert the sequence numbers of the letters, we get 1 2 2 60 3 40, where the sequence numbers are in italics, the gematrical values are in bold. Similarly, the gematrical values of the letters in the second word are 1 30 30 5. When we insert the sequence numbers of the letters, we get 1 1 2 30 3 30 4 5, and so on. When all the numbers are put together, the result is a 56-digit number that is a multiple of 19: 1 1 2 2 60 3 40 2 1 1 2 30 3 30 4 5 3 1 1 2 30 3 200 4 8 5 40 6 50 4 1 1 2 30 3 200 4 8 5 10 6 40 = 19 x 590843895848580686595 . ( 13 found in 1 method even though with other methods we get up to 30
  4. So i have mentioned a combinations in Bismillah Fatiha some are strong some are weak the Strong 1s are in the fixed method of 1, 2, 3, 4, in the Bismillah but u can decide i Shall later put up a post and see how many combinations were found in patterns of 1 2 3 4 etc
  5. 38 combinations of 19 we already mentioned Allah is 2nd word and total numerical value is 66 266 is a multiple of 19 and then we did the 2 attributes of Allah Ar Rahman Ar Raheem which is 3 329 4 289 =divisible by 19 ​then we did 2 66 3 329 4 289/ divisible by 19 now if we take 1st word and the word bism so write it as 1 102 /19 =divisible without a remainder 38 combinations its like a pattern 1 102 2 66 3 329 4 289 / divisible Allah name 2 66 divisible Allah 2 names 3 329 4 289 divisible Allah and his 2 names divisible and just the first word bism 1 102 is divisible by 19
  6. Total number of words 1+2+3+4 = 10 total number of letters 19 1 10 2 19 /19 =5,801 36 combinations of 19 now leading to 37 1 10 2 19 3 102 66 329 289 4 786 /19 =58010163298068047094 reversing it 6874982923222013912011/7 = 982140417603144844573 36-37 combinations of 19 and 28 combinations of 7
  7. we did Allah name and his 2 attributes 2 66 3 329 4 289 /19= divisible we did just the name Allah 266/19 lets do 2 attributes 3 329 4 289/19 = divisible by 19 still 34 combinations of 19 we have up to now but making it 35 lets add total numerical value of each word with total numerical value of each letter with number of letters so e.g 102+2+60+40+3= 207 so 207 1 136 2 664 3 584 4 /19 = divisible no remainder
  8. 4 289 3 329 2 66 1 102/19 no remainder is wrong mistake
  9. I mentioned this before 4 289 3 329 2 66 1 102/19 no remainder now lets do it with number of letters mathematical value 4 13020081040 3 13020084050 2 130305 1 26040
  10. Another MUST SEE< 33 combinations of 19 and 27 combinations of 7 Number 7 number of letters numerical value first and last for 1st word and last word so 1 2 40 ;4 1 40 /7 =divisible lets write total numerical value backwards lets write 1 1st chapter so 1 instead of 102 it will be 201 120166923982/7 =divisible ;lets write number and number of letters in each word so number 1 will link with ;6 2 will link with 6 3 with 3 and 4 4 3 1 6 2 6 3 ;4 4 3/7 = divisible Number 19 or lets write it with 1 2 3 4 Lets write numerical value backwards so instead of 102 it will be 201 so 1 201 2 66 3 923 4 982 /19 =divisible now lets see numerical value of each letter going backwards so 2 60 40 will be written as 04062 1040622503031305048002031404018002031/19=divisible 3 4 is in ther aswell
  11. 6. Number 7 first and last verse first and last word first num of letters n last 17 49 19 43/7 =2498849
  12. Number 7 1. 1 -1st chapter letters in each verse total letters 1-7 2-6 3-5 1 19 43 17 18 12 19 11/7 = NO REMAINDER 2. lets do words in each verse first-last 2-6 3. 1 7 2 6 3 5 4/7 =246,622 4.letters in each word 1 4 9 4 3 2 4 3 /7= No remainder 5. 1 4 1 9 9 4 3/7 202/849 1 1st chapter 4 words 19 letters (1st verse) 9 words 43 letters (last verse)
  13. 10. Lets look at which number is repeated most in letters in each word 5 = 9 times 1 5 5 5 5 5 5 5 5 5 /19=81 871 345 11. Lets look at words in each verse see which is repeated most 4 =3 times 1 4 4 4 =76
  14. 9. 1 10143/19 =5797 10143 is total numerical value of fatiha
  15. Surah fatiha is divided into 2 parts 7.lets look at the beginning of the 2 parts verse 1 and verse 5 lets add first and last letter in each of the 2 verses 1 n 5 3+6+4+6=19 8.13563453 6765687/19=No remainder 1=1st chapter 3 first letter of verse 1 5 first letter of verse 2 6 first letter of verse 3 3 first letter of verse 4 4 first letter of verse 5 5 first letter of verse 6 3 first letter of verse 7 Last letter of each word 6 =verse 1 7 =verse 2 6 =verse 3 5 =verse 4 6 = verse 5 8= verse 6 7 = verse 7 We haven't even looked at the 7's yet but here is 1 for now 1. Number 7= 1 36 57 66 35 46 58 37 /7 = No remainder
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